P=x^2-8x-20

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Solution for P=x^2-8x-20 equation:



=P^2-8P-20
We move all terms to the left:
-(P^2-8P-20)=0
We get rid of parentheses
-P^2+8P+20=0
We add all the numbers together, and all the variables
-1P^2+8P+20=0
a = -1; b = 8; c = +20;
Δ = b2-4ac
Δ = 82-4·(-1)·20
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12}{2*-1}=\frac{-20}{-2} =+10 $
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12}{2*-1}=\frac{4}{-2} =-2 $

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